Enterprise Application: HTTP Server Streams Video using C# (.NET Core), Java (Spring Boot), and Golang

Creating a fully functional video streaming service involves multiple components, and providing a complete example within the scope of a single response is challenging. However, I can provide you with a basic example of how to set up a simple HTTP server that streams video content using C# (.NET Core), Java (Spring Boot), and Golang.

C# (.NET Core) Simple Video Streaming:

using Microsoft.AspNetCore.Builder;
using Microsoft.AspNetCore.Hosting;
using Microsoft.AspNetCore.Http;
using Microsoft.Extensions.DependencyInjection;
using System.IO;

class Program
{
    static void Main()
    {
        var host = new WebHostBuilder()
            .UseKestrel()
            .ConfigureServices(services => services.AddMvc())
            .Configure(app => app.UseMvc())
            .Build();

        host.Run();
    }
}

public class VideoController
{
    [HttpGet("/video")]
    public IActionResult GetVideo()
    {
        var videoPath = "path/to/your/video.mp4"; // Replace with the actual path to your video file
        var stream = new FileStream(videoPath, FileMode.Open);

        return new FileStreamResult(stream, "video/mp4");
    }
}

Java (Spring Boot) Simple Video Streaming:

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.core.io.ClassPathResource;
import org.springframework.core.io.Resource;
import org.springframework.http.MediaType;
import org.springframework.http.ResponseEntity;
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RestController;

@SpringBootApplication
public class VideoStreamingApplication {
    public static void main(String[] args) {
        SpringApplication.run(VideoStreamingApplication.class, args);
    }
}

@RestController
@RequestMapping("/video")
class VideoController {
    @GetMapping
    public ResponseEntity<Resource> getVideo() {
        Resource video = new ClassPathResource("static/video.mp4"); // Replace with the actual path to your video file

        return ResponseEntity.ok()
                .contentType(MediaType.parseMediaType("video/mp4"))
                .body(video);
    }
}

Golang Simple Video Streaming:

package main

import (
    "fmt"
    "net/http"
    "os"
)

func videoHandler(w http.ResponseWriter, r *http.Request) {
    videoPath := "path/to/your/video.mp4" // Replace with the actual path to your video file

    file, err := os.Open(videoPath)
    if err != nil {
        http.Error(w, fmt.Sprintf("Error opening video file: %s", err), http.StatusInternalServerError)
        return
    }
    defer file.Close()

    w.Header().Set("Content-Type", "video/mp4")
    http.ServeContent(w, r, "", file.Stat().ModTime(), file)
}

func main() {
    http.HandleFunc("/video", videoHandler)
    http.ListenAndServe(":8080", nil)
}

In these examples, a basic HTTP server is set up with an endpoint (/video) that streams a video file in response to requests. Replace "path/to/your/video.mp4" with the actual path to your video file.

Note: These examples are simplified and might not handle advanced scenarios like seeking or adaptive streaming. Depending on your requirements, you might need to use specialized libraries or tools for a fully-featured video streaming service.